C#中通过Process运行程序如何获取进程的标准输出

在用C#写一个项目中的工具程序时，需要在C#程序中运行一个命令行的程序，同时将程序的命令行标准输出获取到并显示在指定的文本框中。
查找相关资料找到以下办法，供大家参考。
在创建Process的时候，通过如下方式来实现该功能。
首先，创建ProcessStartInfo：

var p = new Process 
{
    StartInfo = new ProcessStartInfo
    {
        FileName = program.exe,
        Arguments = command line arguments to your executable,
        UseShellExecute = false,
        RedirectStandardOutput = true,
        CreateNoWindow = true
    }
};

然后，用上面创建好的启动信息来启动进程，如下：

p.Start();
while (!p.StandardOutput.EndOfStream)
{
    string line = p.StandardOutput.ReadLine();
    // do something with line
}

另外，也可以参照以下代码，采用同步或异步方式来运行程序，获取命令行标准输出的内容。
同步方式的代码：

static void runCommand()
{
    Process process = new Process();
    process.StartInfo.FileName = cmd.exe;
    process.StartInfo.Arguments = /c DIR; // Note the /c command (*)
    process.StartInfo.UseShellExecute = false;
    process.StartInfo.RedirectStandardOutput = true;
    process.StartInfo.RedirectStandardError = true;
    process.Start();
    //* Read the output (or the error)
    string output = process.StandardOutput.ReadToEnd();
    Console.WriteLine(output);
    string err = process.StandardError.ReadToEnd();
    Console.WriteLine(err);
    process.WaitForExit();
}

异步方式的代码：

static void runCommand() 
{
    //* Create your Process
    Process process = new Process();
    process.StartInfo.FileName = cmd.exe;
    process.StartInfo.Arguments = /c DIR;
    process.StartInfo.UseShellExecute = false;
    process.StartInfo.RedirectStandardOutput = true;
    process.StartInfo.RedirectStandardError = true;
    //* Set your output and error (asynchronous) handlers
    process.OutputDataReceived += new DataReceivedEventHandler(OutputHandler);
    process.ErrorDataReceived += new DataReceivedEventHandler(OutputHandler);
    //* Start process and handlers
    process.Start();
    process.BeginOutputReadLine();
    process.BeginErrorReadLine();
    process.WaitForExit();
}

static void OutputHandler(object sendingProcess, DataReceivedEventArgs outLine) 
{
    //* Do your stuff with the output (write to console/log/StringBuilder)
    Console.WriteLine(outLine.Data);
}